If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( y )
y = 0
y = 0
y = 0
y in (-oo:0) U (0:+oo)
y^-5*((5^3*y^2)/(5^2)) = 0
5*y^-3 = 0 // : 5
y^-3 = 0
y należy do O
y belongs to the empty set
| (5b-4)(2b+1)=0 | | t^2+8t+5=0 | | y-u=at | | 8t-5=3t+1.45 | | t^2+8+5=0 | | 125a^6b^3c^8/25a^6b^2c^9 | | -15+y=-2 | | 4np+7mp= | | (a-7)(a-6)=0 | | (1,56X^(2/3))-(0.65X^(5/3)) | | (x+11)(x+5)=0 | | -4/15=6x/25 | | k+1-2=9-16 | | -1/2a-3/7=11/7-1/2a | | 7x/x^2-16= | | 4-8x=8-12x | | 2m-4(3m-2)=5(6+m)-7 | | 25x^2+90x+44=0 | | 2m-4(3m-2)=5(6+m)+7 | | 9x+35= | | 13x-17= | | 5x^2+24x-9=0 | | 19-1/2=34 | | 19-6/2=34 | | (2p-5q)(5q+2p)= | | 19-19/2=34 | | 19-7/2=34 | | 19-5=68 | | 7x+5=9x-11 | | -3x+9=8-(2x+17) | | 5x-(3-(x-1))=x+3(2x-4) | | 50x+22y=116 |